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Add geometric mean to `statistics` module #71368

Closed 06547701-06a2-4e4a-b672-16a33475101e closed 5 years ago

06547701-06a2-4e4a-b672-16a33475101e commented 8 years ago
BPO 27181
Nosy @rhettinger, @mdickinson, @stevendaprano, @cool-RR, @vadmium, @koobs, @csabella
PRs
  • python/cpython#12638
  • Note: these values reflect the state of the issue at the time it was migrated and might not reflect the current state.

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    GitHub fields: ```python assignee = 'https://github.com/stevendaprano' closed_at = created_at = labels = ['3.8', 'type-feature', 'library'] title = 'Add geometric mean to `statistics` module' updated_at = user = 'https://github.com/cool-RR' ``` bugs.python.org fields: ```python activity = actor = 'rhettinger' assignee = 'steven.daprano' closed = True closed_date = closer = 'rhettinger' components = ['Library (Lib)'] creation = creator = 'cool-RR' dependencies = [] files = [] hgrepos = [] issue_num = 27181 keywords = ['patch'] message_count = 45.0 messages = ['266948', '266969', '267051', '267253', '267990', '268008', '268020', '268022', '270025', '270026', '270033', '272214', '272217', '272218', '272224', '272225', '272488', '272504', '272525', '272526', '272640', '272659', '272807', '272880', '272881', '272882', '272913', '272970', '275927', '276057', '276060', '276151', '278056', '278059', '278076', '278078', '300918', '335662', '335720', '338742', '339082', '339094', '339319', '339579', '339580'] nosy_count = 8.0 nosy_names = ['rhettinger', 'mark.dickinson', 'steven.daprano', 'cool-RR', 'python-dev', 'martin.panter', 'koobs', 'cheryl.sabella'] pr_nums = ['12638'] priority = None resolution = 'fixed' stage = 'resolved' status = 'closed' superseder = None type = 'enhancement' url = 'https://bugs.python.org/issue27181' versions = ['Python 3.8'] ```

    rhettinger commented 8 years ago

    Steven, this seems like a reasonable suggestion (though I would expect someone else will immediately suggest a harmonic mean as well). Is this within the scope of what you were trying to do with the statistics module?

    stevendaprano commented 8 years ago

    On Thu, Jun 02, 2016 at 09:04:54PM +0000, Raymond Hettinger wrote:

    Steven, this seems like a reasonable suggestion (though I would expect someone else will immediately suggest a harmonic mean as well). Is this within the scope of what you were trying to do with the statistics module?

    Yes, I think it is reasonable too. I'll aim to get this in to 3.6.

    06547701-06a2-4e4a-b672-16a33475101e commented 8 years ago

    To complicate things further...

    I implemented a geometric mean on my own, and then I figured out what I really want is a weighted geometric mean, so I implemented that for myself. If you'd want to include that, that'll be cool. Actually I'm not sure if the goal of the statistics module is to be comprehensive or minimal. I'm hoping it's meant to be comprehensive. But then I'd guess there would be a lot of things you'd want to add except my little feature.

    06547701-06a2-4e4a-b672-16a33475101e commented 8 years ago

    And of course, if the goal of the statistics module is to be comprehensive, one should ask himself what should be the difference between this new module and a mature statistics module like scipy.stats, and whether we should try to copy the features of off scipy.stats.

    mdickinson commented 8 years ago

    Choice of algorithm is a bit tricky here. There are a couple of obvious algorithms that work mathematically but result in significant accuracy loss in an IEEE 754 floating-point implementation: one is exp(mean(map(log, my_numbers))), where the log calls can introduce significant loss of information, and the other is prod(x**(1./len(my_numbers)) for x in my_numbers), where the **(1./n) operation similarly discards information. A better algorithm numerically is prod(my_numbers)**(1./len(my_numbers)), but that's likely to overflow quickly for large datasets (and/or datasets containing large values).

    I'd suggest something along the lines of prod(my_numbers)**(1./len(my_numbers)), but keeping track of the exponent of the product separately and renormalizing where necessary to avoid overflow.

    There are also algorithms for improved accuracy in a product, along the same lines as the algorithm used in fsum. See e.g., the paper "Accurate Floating-Point Product and Exponentiation" by Stef Graillat. [1] (I didn't know about this paper: I just saw a reference to it in a StackOverflow comment [2], which reminded me of this issue.)

    [1] http://www-pequan.lip6.fr/~graillat/papers/IEEE-TC-prod.pdf [2] http://stackoverflow.com/questions/37715250/safe-computation-of-geometric-mean

    mdickinson commented 8 years ago

    On the other hand, apparently exp(mean(log(...))) is good enough for SciPy: its current implementation looks like this:

    def gmean(a, axis=0):
        a, axis = _chk_asarray(a, axis)
        log_a = ma.log(a)
        return ma.exp(log_a.mean(axis=axis))
    stevendaprano commented 8 years ago

    On Thu, Jun 09, 2016 at 09:24:04AM +0000, Mark Dickinson wrote:

    On the other hand, apparently exp(mean(log(...))) is good enough for SciPy:

    Hmm, well, I don't have SciPy installed, but I've found that despite their (well-deserved) reputation, numpy (and presumably scipy) often have rather naive algorithms that can lose accuracy rather spectacularly.

    py> statistics.mean([1e50, 2e-50, -1e50, 2e-50]) 1e-50 py> np.mean(np.array([1e50, 2e-50, -1e50, 2e-50])) 5e-51

    py> statistics.mean([1e50, 2e-50, -1e50, 2e-50]1000) 1e-50 py> np.mean(np.array([1e50, 2e-50, -1e50, 2e-50]1000)) 5.0000000000000002e-54

    On the other hand, np is probably a hundred times (or more) faster, so I suppose accuracy/speed makes a good trade off.

    mdickinson commented 8 years ago

    Hmm, well, I don't have SciPy installed, but I've found that despite their (well-deserved) reputation, numpy (and presumably scipy) often have rather naive algorithms that can lose accuracy rather spectacularly.

    Agreed. And as Ram Rachum hinted, there seems little point aiming to duplicate things that already exist in the de facto standard scientific libraries. So I think there's a place for a non-naive carefully computed geometric mean in the std. lib. statistics module, but I wouldn't see the point of simply adding an exp-mean-log implementation (not that anyone is advocating that).

    stevendaprano commented 8 years ago

    Does anyone have any strong feeling about the name for these functions?

    gmean and hmean;

    geometric_mean and harmonic_mean

    And "subcontrary_mean" is not an option :-)

    rhettinger commented 8 years ago

    I would like to see them spelled-out: geometric_mean and harmonic_mean

    mdickinson commented 8 years ago

    I would like to see them spelled-out: geometric_mean and harmonic_mean

    +1

    1762cc99-3127-4a62-9baf-30c3d0f51ef7 commented 8 years ago

    New changeset 9eb5edfcf604 by Steven D'Aprano in branch 'default': bpo-27181 add geometric mean. https://hg.python.org/cpython/rev/9eb5edfcf604

    06547701-06a2-4e4a-b672-16a33475101e commented 8 years ago

    Thanks for the patch Steven! I won't comment about the code because I don't know enough about these algorithms, but I'm thinking, since you also did a refactoring of the statistics module, maybe these should be two separate patches/commits so it'll be easy to see which part is the new feature and which part is moving existing code around?

    06547701-06a2-4e4a-b672-16a33475101e commented 8 years ago

    Also... I like the detailed docstrings with the real-life examples! That stuff helps when coding and using an unfamiliar function (since I see the docs in a panel of my IDE), so I wish I'd see more detailed docstrings like these ones in the standard library. For geometric_mean, maybe I'd add one sentence that describes how the geometric mean is calculated.

    stevendaprano commented 8 years ago

    On Tue, Aug 09, 2016 at 06:44:22AM +0000, Ram Rachum wrote:

    For geometric_mean, maybe I'd add one sentence that describes how the geometric mean is calculated.

    What do you mean? As in, the mathematical definition of geometric mean?

    Or do you mean a one sentence description of the algorithm?

    06547701-06a2-4e4a-b672-16a33475101e commented 8 years ago

    I meant the mathematical definition.

    vadmium commented 8 years ago

    Tests fail on a Power PC buildbot:

    http://buildbot.python.org/all/builders/PPC64LE%20Fedora%203.x/builds/1476/steps/test/logs/stdio \====================================================================== FAIL: testExactPowers (test.test_statistics.Test_Nth_Root) (i=29, n=11) ----------------------------------------------------------------------

    Traceback (most recent call last):
      File "/home/shager/cpython-buildarea/3.x.edelsohn-fedora-ppc64le/build/Lib/test/test_statistics.py", line 1216, in testExactPowers
        self.assertEqual(self.nroot(x, n), i)
    AssertionError: 29.000000000000004 != 29

    ====================================================================== FAIL: testExactPowersNegatives (test.test_statistics.Test_Nth_Root) (i=-29, n=11) ----------------------------------------------------------------------

    Traceback (most recent call last):
      File "/home/shager/cpython-buildarea/3.x.edelsohn-fedora-ppc64le/build/Lib/test/test_statistics.py", line 1228, in testExactPowersNegatives
        self.assertEqual(self.nroot(x, n), i)
    AssertionError: -29.000000000000004 != -29
    mdickinson commented 8 years ago

    What no patch for pre-commit review?!

    For computing nth roots, it may be worth special-casing the case n=2: for floats, math.sqrt is likely to be faster and more precise than an ad-hoc algorithm. (Indeed, I'd expect it to be perfectly correctly rounded on the vast majority of current machines.)

    stevendaprano commented 8 years ago

    I thought about special-casing n=2 to math.sqrt, but as that's an implementation detail I can make that change at any time. According to my testing, math.pow(x, 0.5) is no worse than sqrt, so I'm not sure if there's any advantage to having yet another branch.

    I'd be interested in special-casing n=3 to math.cbrt (if and when it exists) now that its a standard C99 function.

    mdickinson commented 8 years ago

    According to my testing, math.pow(x, 0.5) is no worse than sqrt.

    It certainly is worse than sqrt, both in terms of speed and accuracy. Whether the difference is enough to make it worth special-casing is another question, of course, and as you say, that can happen later.

    stevendaprano commented 8 years ago

    I've created a new issue to track the loss of accuracy on PowerPC: http://bugs.python.org/issue27761

    mdickinson commented 8 years ago

    A failing case:

    >>> statistics.geometric_mean([0.7 for _ in range(5000)])
    Traceback (most recent call last):
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 362, in float_nroot
        isinfinity = math.isinf(x)
    OverflowError: int too large to convert to float
    
    During handling of the above exception, another exception occurred:
    
    Traceback (most recent call last):
      File "<stdin>", line 1, in <module>
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 595, in geometric_mean
        s = 2**p * _nth_root(2**q, n)
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 346, in nth_root
        return _nroot_NS.float_nroot(x, n)
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 364, in float_nroot
        return _nroot_NS.bignum_nroot(x, n)
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 489, in bignum_nroot
        b = 2**q * _nroot_NS.nroot(2**r, n)
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 384, in nroot
        r1 = math.pow(x, 1.0/n)
    OverflowError: int too large to convert to float
    ned-deily commented 8 years ago

    FTR, multiple platforms are failing in various ways, not just PPC64, so bpo-27761 was expanded to cover them and has been marked as a "release blocker".

    vstinner commented 8 years ago

    Failure on s390x Debian 3.x:

    http://buildbot.python.org/all/builders/s390x%20Debian%203.x/builds/1455/steps/test/logs/stdio

    \====================================================================== FAIL: testExactPowers (test.test_statistics.Test_Nth_Root) (i=29, n=11) ----------------------------------------------------------------------

    Traceback (most recent call last):
      File "/home/dje/cpython-buildarea/3.x.edelsohn-debian-z/build/Lib/test/test_statistics.py", line 1216, in testExactPowers
        self.assertEqual(self.nroot(x, n), i)
    AssertionError: 29.000000000000004 != 29

    ====================================================================== FAIL: testExactPowersNegatives (test.test_statistics.Test_Nth_Root) (i=-29, n=11) ----------------------------------------------------------------------

    Traceback (most recent call last):
      File "/home/dje/cpython-buildarea/3.x.edelsohn-debian-z/build/Lib/test/test_statistics.py", line 1228, in testExactPowersNegatives
        self.assertEqual(self.nroot(x, n), i)
    AssertionError: -29.000000000000004 != -29
    1762cc99-3127-4a62-9baf-30c3d0f51ef7 commented 8 years ago

    New changeset 54288b160243 by Victor Stinner in branch 'default': Issue bpo-27181: Skip tests known to fail until a fix is found https://hg.python.org/cpython/rev/54288b160243

    vstinner commented 8 years ago

    I would like to use buildbots to check for regressions, but I see a lot of red buildbots, so buildbots became useless :-/

    I skipped failing test_statistics tests, since failures are known.

    I put the priority to "release blocker".

    I suggest to either revert the change or find a fix before 3.6b1.

    koobs commented 8 years ago

    For posterity, the following failure was observed on all (9/10/11(current) FreeBSD buildbots:

    \====================================================================== FAIL: testFraction (test.test_statistics.Test_Nth_Root) ----------------------------------------------------------------------

    Traceback (most recent call last):
      File "/usr/home/buildbot/python/3.x.koobs-freebsd9/build/Lib/test/test_statistics.py", line 1247, in testFraction
        self.assertEqual(self.nroot(x**12, 12), float(x))
    AssertionError: 1.1866666666666665 != 1.1866666666666668
    mdickinson commented 8 years ago
    self.assertEqual(self.nroot(x\*\*12, 12), float(x))

    AssertionError: 1.1866666666666665 != 1.1866666666666668

    That looks like a case where the test should simply be weakened to an assertAlmostEqual with a suitable tolerance; there's no strong reason to expect that nroot will give a faithfully rounded result in this case or any other.

    stevendaprano commented 8 years ago

    As discussed with Ned by email, I'm currently unable to build 3.6 and won't have time to work on this before b1. As discussed on bpo-27761 my tests here are too strict and should be loosened, e.g. from assertEqual to assertAlmostEqual. Ned wrote:

    "If you are only planning to make changes to the tests themselves, I think that can wait for b2."

    I have no plans to change the publicly visible interface of geometric_mean.

    mdickinson commented 8 years ago

    Steven: any thoughts about the

    statistics.geometric_mean(0.7 for _ in range(5000))

    failure? Should I open a separate bug report for that, or would you rather address it as part of this issue?

    vstinner commented 8 years ago
    >>> statistics.geometric_mean([0.7 for _ in range(5000)])
    Traceback (most recent call last):
      File "/Users/mdickinson/Python/cpython-git/Lib/statistics.py", line 362, in float_nroot
        isinfinity = math.isinf(x)
    OverflowError: int too large to convert to float

    => see also issue bpo-27975

    stevendaprano commented 8 years ago

    On Mon, Sep 12, 2016 at 03:35:14PM +0000, Mark Dickinson wrote:

    statistics.geometricmean(0.7 for in range(5000))

    I've raised a new ticket bpo-28111

    stevendaprano commented 8 years ago

    I'm sorry to say that due to technical difficulties, geometric mean is not going to be in a fit state for beta 2 of 3.6, and so is going to be removed and delayed until 3.7.

    1762cc99-3127-4a62-9baf-30c3d0f51ef7 commented 8 years ago

    New changeset 9dce0e41bedd by Steven D'Aprano in branch 'default': Issue bpo-27181 remove geometric_mean and defer for 3.7. https://hg.python.org/cpython/rev/9dce0e41bedd

    1762cc99-3127-4a62-9baf-30c3d0f51ef7 commented 8 years ago

    New changeset de0fa478c22e by Steven D'Aprano in branch '3.6': Issue bpo-27181 remove geometric_mean and defer for 3.7. https://hg.python.org/cpython/rev/de0fa478c22e

    ned-deily commented 8 years ago

    Thanks, Steven. Actually, we needed to remove geometric_mean from the 3.6 branch, not the default branch (which will become 3.7). I backported your removal patch to 3.6. Feel free to reapply geometric_mean to the default branch at your leisure.

    csabella commented 7 years ago

    I was wondering if this has been taken up again for 3.7? Thanks!

    csabella commented 5 years ago

    Updating the version in case this wanted to be considered for 3.8.

    rhettinger commented 5 years ago

    Updating the version in case this wanted to be considered for 3.8.

    Yes. It would be nice to get this wrapped-up.

    rhettinger commented 5 years ago

    Almost three years have passed.

    In the spirit of "perfect is the enemy of good", would it be reasonable to start with a simple, fast implementation using exp-mean-log? Then if someone wants to make it more accurate later, they can do so.

    In some quick tests, I don't see much of an accuracy loss. It looks to be plenty good enough to use as a starting point:

    --- Accuracy experiments ---

    >> from decimal import Decimal >> from functools import reduce >> from operator import mul >> from random import expovariate, triangular >> from statistics import fmean

    >>> # https://www.wolframalpha.com/input/?i=geometric+mean+12,+17,+13,+5,+120,+7
    >>> data = [12, 17, 13, 5, 120, 7]
    >>> print(reduce(mul, map(Decimal, data)) ** (Decimal(1) / len(data)))
    14.94412420173971227234687688
    >>> exp(fmean(map(log, map(fabs, data))))
    14.944124201739715
    
    >>> data = [expovariate(50.0) for i in range(1_000)]
    >>> print(reduce(mul, map(Decimal, data)) ** (Decimal(1) / len(data)))
    0.01140902688569587677205587938
    >>> exp(fmean(map(log, map(fabs, data))))
    0.011409026885695879
    
    >>> data = [triangular(2000.0, 3000.0, 2200.0) for i in range(10_000)]
    >>> print(reduce(mul, map(Decimal, data)) ** (Decimal(1) / len(data)))
    2388.381301718524160840023868
    >>> exp(fmean(map(log, map(fabs, data))))
    2388.3813017185225
    
    >>> data = [lognormvariate(20.0, 3.0) for i in range(100_000)]
    >>> min(data), max(data)
    (2421.506538652375, 137887726484094.5)
    >>> print(reduce(mul, map(Decimal, data)) ** (Decimal(1) / len(data)))
    484709306.8805352290183838500
    >>> exp(fmean(map(log, map(fabs, data))))
    484709306.8805349
    stevendaprano commented 5 years ago

    In the spirit of "perfect is the enemy of good", would it be reasonable to start with a simple, fast implementation using exp-mean-log? Then if someone wants to make it more accurate later, they can do so.

    I think that is a reasonable idea. On the basis that something is better than nothing, go ahead. We can discuss accuracy and speed issues later.

    Getting some tricky cases down for reference:

    # older (removed) implementation py> geometric_mean([7]2) 7.0 py> geometric_mean([7]15) 7.0

    # Raymond's newer (faster) implementation py> exp(fmean(map(log, [7]2))) 6.999999999999999 py> exp(fmean(map(log, [7]15))) 6.999999999999999

    py> geometric_mean([3,27]) 9.0 py> geometric_mean([3,27]*5) 9.0

    py> exp(fmean(map(log, [3,27]))) 9.000000000000002 py> exp(fmean(map(log, [3,27]*5))) 8.999999999999998

    py> x = 2.5e15 py> geometric_mean([x]100) 2500000000000000.0 py> exp(fmean(map(log, [x]100))) 2499999999999999.5

    On the other hand, sometimes rounding errors work in our favour:

    py> geometric_mean([1e50, 1e-50]) # people might expect 1.0 0.9999999999999998 py> 1e-50 == 1/(1e50) # even though they aren't quite inverses False

    py> exp(fmean(map(log, [1e50, 1e-50]))) 1.0

    rhettinger commented 5 years ago

    On the basis that something is better than nothing, go ahead. We can discuss accuracy and speed issues later.

    Thanks. I'll put together a PR for your consideration.

    rhettinger commented 5 years ago

    Steven, how does this look?

    https://patch-diff.githubusercontent.com/raw/python/cpython/pull/12638.diff

    rhettinger commented 5 years ago

    New changeset 6463ba3061bd311413d2951dc83c565907e10459 by Raymond Hettinger in branch 'master': bpo-27181: Add statistics.geometric_mean() (GH-12638) https://github.com/python/cpython/commit/6463ba3061bd311413d2951dc83c565907e10459

    rhettinger commented 5 years ago

    Feel free to reopen this if something further needed to be changed or discussed.