Open momandine opened 6 years ago
There must be a little more going on than you show, since if I type that example into mypy:
class Base:
def foo(self) -> None:
a = self.static_foo()
class Sub(Base):
static_foo = staticmethod(lambda: 5)
I get a much simpler error:
_.py:3: error: "Base" has no attribute "static_foo"
Well, this example doesn't error at all, which is closer:
1 from typing import Any, Dict
2
3 class Base(object):
4 def __init__(self, dikt):
5 # type: (Dict[Any, Any]) -> None
6 object.__setattr__(self, '_dict', dikt)
7
8 def __getattr__(self, name):
9 # type: (str) -> Any
10 return self._dict[name]
11
12 def __setattr__(self, name, val):
13 # type: (str, Any) -> None
14 if name in self._dict:
15 self._dict[name] = val
16 else:
17 object.__setattr__(self, name, val)
18
19 def foo(self):
20 # type: () -> None
21 a = self.static_foo()
22
23
24
25 class SubClass(Base):
26 static_foo = staticmethod(lambda: 5)
This does repro (though in my actual example, there is no staticmethod declared on the base class (???).
1 from typing import Any, Dict
2
3 class Base(object):
4 def __init__(self, dikt):
5 # type: (Dict[Any, Any]) -> None
6 object.__setattr__(self, '_dict', dikt)
7
8 def __getattr__(self, name):
9 # type: (str) -> Any
10 return self._dict[name]
11
12 def __setattr__(self, name, val):
13 # type: (str, Any) -> None
14 if name in self._dict:
15 self._dict[name] = val
16 else:
17 object.__setattr__(self, name, val)
18
19 def foo(self):
20 # type: () -> None
21 a = self.static_foo()
22
23 @staticmethod
24 def static_foo():
25 # type: () -> int
26 return 0
27
28
29 class SubClass(Base):
30 static_foo = staticmethod(lambda: 5)
31
32 def __init__(self, *args, **kwargs):
33 # type: (*Any, **Any) -> None
34 super(SubClass, self).__init__(*args, **kwargs)
More minimal repro:
class Base(object):
def foo(self) -> None:
a = self.static_foo()
@staticmethod
def static_foo() -> int:
return 0
class SubClass(Base):
static_foo = staticmethod(lambda: 5)
And to clarify, this gives the following error:
_.py:16: error: Incompatible types in assignment (expression has type "staticmethod", base class "Base" defined the type as "Callable[[], int]")
Now it's very clear that the error is caused by mypy's lack of understanding of how staticmethod()
relates to @staticmethod
.
As to why it gave this same error for you with the real version of the original code, even though there was no definition of static_foo
in the base class there, I'm still not sure. But maybe you don't care and you would just like mypy's understanding of staticmethod()
to be improved?
Improving mypy's understanding of inline usage of staticmethod seems tractable/higher priority. Given how clever this code is, someone may have monkey patched something somewhere to the same effect of the minimal example.
The false-positive error is no longer emitted on mypy 0.930+.
@AlexWaygood this is error is back, at least with mypy 0.950 and 3.7 <= python <= 3.9: https://mypy-play.net/?mypy=0.950&python=3.8&gist=1e25a16047bae31555e210da7797f640
@AlexWaygood this is error is back, at least with mypy 0.950 and 3.7 <= python <= 3.9: https://mypy-play.net/?mypy=0.950&python=3.8&gist=1e25a16047bae31555e210da7797f640
Hah! This bug was never fixed. The reason I thought it was is because I was testing on 3.10, and the typeshed stub (correctly) states that staticmethod.__call__
was added in 3.10. This means that there's no false positive error on 3.10, but it's not because the mypy bug is fixed, it's because the typeshed stub is different if you're running on 3.10.
Thanks @youtux :)
A simplification of some old code I am trying to add mypy to:
Results in the error:
error: Incompatible types in assignment (expression has type "staticmethod", base class "Job" defined the type as "Callable[[], int]")
Oddly, as far as I can tell,
static_foo
is not actually defined on the base class.This is using Dropbox's mypy setup, with --strict-optional. I am actually not sure which version we're on, but can look it up and edit this issue.