Open fabioz opened 4 years ago
I didn't follow everything yet (it takes me a while) but does the same thing happen if you use a digger ale instead of '_'? IIRC there's a special case for that somewhere. (But I may very well be wrong, sorry.)
Changing _
to any other name yields the same results.
minimal example:
from typing import TypeVar, Protocol, Callable
F = TypeVar('F')
foo: Callable[[F], F] = lambda x: x
class IFoo(Protocol):
def some_method(self) -> bool: ...
class Foo(object):
def __init__(self) -> None:
blah: IFoo = self
#@foo
def some_method(self) -> str:
pass
uncommenting @foo
removes error and it's not supposed to do that
@Akuli Thanks for the translation. :-)
This feels like it’s because mypy doesn’t have the proper type for a decorated method when it checks the init body.
Definitely a bug, not simple to fix, so use the workaround of putting the check after the class.
putting the check after the class requires creating an instance of the class just for the check
Actually, I ended up doing a different approach (using a class decorator to check the type instead of using the __init__
), with the code below...
So, while the issue persists, I already found another workaround where things work for me.
Just for reference, I'm using the check_implements
decorator as below:
from typing import TypeVar, Protocol, Callable
F = TypeVar('F')
foo: Callable[[F], F] = lambda x: x
class IFoo(Protocol):
def some_method(self) -> bool: ...
def check_implements(_:F) -> Callable[[F], F]:
def method(cls):
return cls
return method
@check_implements(IFoo) # Properly complains here.
class Foo(object):
@foo
def some_method(self) -> str:
pass
Actually, sorry, that doesn't work as I expected... I'm still checking for a usable workaround.
You could put the check after the class inside if typing.TYPE_CHECKING:
, which prevents it from working at runtime.
Or you could add a dummy method at the end of the class with the check on self
.
I did another simpler approach with class decorators which seems to work:
def typecheck_ifoo(foo: Type[IFoo]):
return foo
@typecheck_ifoo
class Foo(object):
....
it requires to define one method for each interface, but I think that's a bit better than having it at the end or out of the class.
But if class decorators were implemented properly that would give Foo
the type Any
.
But if class decorators were implemented properly that would give
Foo
the typeAny
.
I agree it's not ideal... do you see any other way to have such a typecheck as a class decorator (with the current set of features from Mypy)?
-- if possible I'd really like to have this close to the start of the class (as a class decorator or __init__
and due to this bug the __init__
isn't an option).
Is there a reason your class can't just inherit from the protocol? IIUC PEP 554 says that should be possible.
Is there a reason your class can't just inherit from the protocol? IIUC PEP 554 says that should be possible.
I could, but it doesn't give me type errors if I forget to implement something.
i.e.:
class IFoo(Protocol):
def method(self) -> str:...
def method2(self) -> str:...
class Foo(IFoo):
def method(self) -> str:...
# method2 not there, but it doesn't complain
It would complain if the methods were abstract in the Protocol class.
I still couldn't get MyPy to complain with the code below... It only seems to complain if I call some function expecting IFoo
where the typing is not satisfied, not just from a wrong class declaration (which is what I'm attempting to do).
from abc import abstractmethod
from typing import Protocol
class IFoo(Protocol):
@abstractmethod
def method(self) -> str:...
@abstractmethod
def method2(self) -> str:...
class Foo(IFoo):
def method(self) -> str:...
# method2 not there, but it doesn't complain
try adding Foo()
to the end of that file to actually create an instance, it will error
Yes, I know it'll error if I try to instance or try to call some method, but the whole point is that I want to type-check some class to conform to some interface without having to create an instance or do some declaration at the end of the class (like what would happen when you implement some java interface).
I'm confused. Why would you create classes without ever instantiating them (and getting the error)?
Oh, I would instance it and get the error somewhere, but the error would likely only appear in some test case (if I'm doing a library for others) or some other place where I'm using that class (which may be very far apart from the class implementation), whereas I'd like to have such an error close to the class declaration/name (near the actual class
keyword)...
Is this such an odd case? (Personally, I find it a bit odd to have protocols and not being able to know if a class implementation conforms to it in the class implementation itself, but maybe my views on how typing should work are too biased from java interfaces)
I would say practicality beats purity. You still get the name of the class in the error message and even a list of missing methods.
But then it's not much better than doing it in runtime if I have to look somewhere else -- just to note, I actually do have such a decorator that checks the class during runtime and gives the error at the class declaration: https://github.com/fabioz/pyvmmonitor-core/blob/master/pyvmmonitor_core/interface.py#L220, or I could use ABCs, but I thought type-checking would allow me to get the error earlier... it's definitely one of the selling points for me ;).
I believe this is a bug (explanation below).
I expected to be able to statically check a case by checking whether
self
matches a given protocol (with thecheck_implements
below).This seems to work, but if the method is decorated (with the
implements
as shown in the code below) it doesn't validate properly that a method return type is wrong.i.e.: in the code below I expected that the
_: IFoo = check_implements(self)
line gives an error because the protocol declaration expects abool
return, whereas the method implementation says it returns astr
.I think this is a bug because the same type-check later on says that the implementation doesn't conform to the protocol if done outside of the class -- as
_: IFoo = check_implements(Foo())
, so, it does something on__init__
and a different thing if out of the__init__
. Besides, it works if the function is not decorated.Note: even if I do
_: IFoo = check_implements(Foo())
in the__init__
it doesn't validate properly (so, it doesn't seem related toself
-- and it works as expected if the function is not decorated).