dr-kinder
commented
3 weeks ago With single X and Z gates, you cannot put either state into a superposition of |0> and |1>. Z multiplies each state by ±1 and X flips each state. You need H to get a superposition: H|0> = |0> + |1>. After this, the CNOT gate can entangle two qbits. With additional Z and X gates, you can create any of the 4 bell states.
why Can't i build a bell state circuit with single z and x and cnot gate but it's possible with H gate... (Lab1) any help is greatly appreciated