Open fdmalone opened 4 months ago
In general a block encoding will only be accurate to some $\epsilon$ which is typically tied back to (potentially several) $\epsilon$'s from state preparation. It's currently not exposed in Prepare. The issue is to add this.
xref #967
In general a block encoding will only be accurate to some $\epsilon$ which is typically tied back to (potentially several) $\epsilon$'s from state preparation. It's currently not exposed in Prepare. The issue is to add this.