Open sswatson opened 3 years ago
It seems that column transformation functions defined using macros can behave differently than functions defined without macros. Here's an example:
using Match, DataFrames, Query df = DataFrame(a = [1, 2], b = [3, missing]) f(x) = @match x begin 3 => "three" _ => missing end df |> @map({_..., c = f(_.b)}) |> @replacena("successfully replaced")
The output still has NAs in it, despite the final @replacena command.
@replacena
If I replace f with an equivalent version without macros (even just the one obtained by expanding the macro), this works as expected.
f
It seems that column transformation functions defined using macros can behave differently than functions defined without macros. Here's an example:
The output still has NAs in it, despite the final
@replacena
command.If I replace
f
with an equivalent version without macros (even just the one obtained by expanding the macro), this works as expected.