Confusion about `enexprs`

[Longfei2]

why does enexprs inside function return the quosure when using embrace operator {{? This is inconsistent with help document: return the naked expression? see the example as below:

test1 <- function(...){

  print(rlang::enexprs(...))
  m <- rlang::enexprs(...)
  print(m)
  print(lapply(m, typeof))

}

test2 <- function(x){
  test1({{x}})
}

Could you please help me understand this function?

[Longfei2]

I have retrieved the issue #1523, thank you.