Excuse me.Why can't local video play? How should I use "VideoPlay "? Thank you very much! （just now， I've taken care of it... ）

[Antonio0307]

self.templatetest = gui.VideoPlayer( video="https://prod-streaming-video-msn-com.akamaized.net/ba258271-89c7-47bc-9742-bcae67c23202/f7ff4fe4-1346-47bb-9466-3f4662c1ac3a.mp4",

poster='',

        autoplay=True,
        loop=True,
        type='video/mp4',
        style='left: 0%; top: 0%; width: 100%; height: 90%')

====================================================== That way, OK.

[Antonio0307]

I've taken care of it.................................................：）

[dddomodossola]

Hello @Antonio0307 ,

Of course you can play local video files. Be careful about:

• supported file formats = Video widget supports the html5 file formats. Please look at this:https://stackoverflow.com/questions/5959833/what-are-all-the-formats-of-video-supported-by-html5
• resource path = for local files you should respect the remi resource filenames.

Example:

import remi.gui as gui
from remi import start, App

class MyApp(App):
    def __init__(self, *args):
        #here I define my resource path
        res_path = "C:/myfolder/"
        super(MyApp, self).__init__(*args, static_file_path={'myres':res_path})
    def main(self):
        main_container = gui.VBox(width=300, height=200, style={'margin': '0px auto'})

        #please look at the video file name, it starts with "/myres:" which is the folder identification
        video = gui.VideoPlayer("/myres:video.mp4", autoplay=True, loop=True, width="100%")
        main_container.append(video)

        return main_container

if __name__ == "__main__":
    start(MyApp, address='0.0.0.0', port=0, start_browser=True, username=None, password=None)

Kind Regards

[Antonio0307]

Hello @Antonio0307 ,

Of course you can play local video files. Be careful about:

• supported file formats = Video widget supports the html5 file formats. Please look at this:https://stackoverflow.com/questions/5959833/what-are-all-the-formats-of-video-supported-by-html5
• resource path = for local files you should respect the remi resource filenames.

Example:

import remi.gui as gui
from remi import start, App

class MyApp(App):
    def __init__(self, *args):
        #here I define my resource path
        res_path = "C:/myfolder/"
        super(MyApp, self).__init__(*args, static_file_path={'myres':res_path})
    def main(self):
        main_container = gui.VBox(width=300, height=200, style={'margin': '0px auto'})

        #please look at the video file name, it starts with "/myres:" which is the folder identification
        video = gui.VideoPlayer("/myres:video.mp4", autoplay=True, loop=True, width="100%")
        main_container.append(video)

        return main_container

if __name__ == "__main__":
    start(MyApp, address='0.0.0.0', port=0, start_browser=True, username=None, password=None)

Kind Regards

Thank you for your reply！：）