Closed robertnishihara closed 8 years ago
This also reduces the timeout from one minute to 5 seconds when you submit a function that hasn't been registered.
Now, if you do
import ray ray.init(start_ray_local=True, num_workers=0) @ray.remote def f(): return 1 f.remote()
It will throw the exception
--------------------------------------------------------------------------- error Traceback (most recent call last) <ipython-input-4-520f46ece26b> in <module>() ----> 1 f.remote(3) /Users/rkn/Workspace/ray/lib/python/ray/worker.pyc in func_call(*args, **kwargs) 1111 # the usual behavior of immutable remote objects. 1112 return func(*copy.deepcopy(args)) -> 1113 objectids = _submit_task(func_name, args) 1114 if len(objectids) == 1: 1115 return objectids[0] /Users/rkn/Workspace/ray/lib/python/ray/worker.pyc in _submit_task(func_name, args, worker) 1056 which cannot be serialized. 1057 """ -> 1058 return worker.submit_task(func_name, args) 1059 1060 def _mode(worker=global_worker): /Users/rkn/Workspace/ray/lib/python/ray/worker.pyc in submit_task(self, func_name, args) 416 args = [arg if isinstance(arg, raylib.ObjectID) else put(arg, worker=self) for arg in args] 417 task_capsule = raylib.serialize_task(self.handle, func_name, args) --> 418 objectids = raylib.submit_task(self.handle, task_capsule) 419 return objectids 420 error: No workers have registered with the scheduler, so this function cannot be run.
This also reduces the timeout from one minute to 5 seconds when you submit a function that hasn't been registered.
Now, if you do
It will throw the exception