Closed Yard1 closed 4 years ago
Hyperopt, confusingly, has bounds for it's log uniform space (hp.loguniform) set to [exp(low), exp(high)]. Therefore, in order to ensure consistency, we need to first logarithm them.
hp.loguniform
[exp(low), exp(high)]
Hyperopt, confusingly, has bounds for it's log uniform space (
hp.loguniform
) set to[exp(low), exp(high)]
. Therefore, in order to ensure consistency, we need to first logarithm them.