preexec() does not work where as precmd() is working as intended.

rcaloras / bash-preexec

⚡ preexec and precmd functions for Bash just like Zsh.

MIT License

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preexec() does not work where as precmd() is working as intended. #145

Closed NikhilBayyavarapu closed 1 year ago

NikhilBayyavarapu commented 1 year ago

Using Pop OS, bash version 5.1.16(1)-release (x86_64-pc-linux-gnu)

1) Cloned the repo. 2) Sourced the bash-preexec.sh file. 3) Defined the preexec() and precmd() functions.

precmd() is working where as preexec() doesn't work. Even tried enabling the subshell support variable.

Did not source the contents of bash-preexec.sh file into my .bashrc as I just wanted to test this out.

Edit : Working fine now. Fig was causing the issue. Uninstalled fig and preexec() is now working fine. Thanks.

dimo414 commented 1 year ago

If you're using Fig (i.e. you're at Google) bash-preexec is likely already installed in your system by default. The issue might have been that you were installing it a second time and overwriting the existing script and functions. Better to use the function arrays in any case.