Closed brcrista closed 4 years ago
This requires C# 9's new T? annotations for unconstrained generic types. This follows how Max() and Min() are annotated.
T?
Max()
Min()
For simplicity in the CI builds, this goes ahead and upgrades the tests to .NET 5.0. This produces some warnings which will need to be fixed later.
This requires C# 9's new
T?annotations for unconstrained generic types. This follows howMax()andMin()are annotated.For simplicity in the CI builds, this goes ahead and upgrades the tests to .NET 5.0. This produces some warnings which will need to be fixed later.