Closed sunilnandihalli closed 3 years ago
I would have expected (s/transform s/ALL identity "abc") to return "abc" but it returns (\c \b \a).
I realized we can just do (s/transform [(s/parser sequence #(apply str %))] identity "abcde")
I would have expected (s/transform s/ALL identity "abc") to return "abc" but it returns (\c \b \a).