Closed GoogleCodeExporter closed 8 years ago
additional notes: the content of show is parsed as "1\r" and in the next step,
the code tries to look up "jan1\r" which does not exist (only "jan1" does)
Original comment by nico.kru...@googlemail.com
on 26 Oct 2012 at 4:54
probably all variants of "newline" should be seen as such: "\n", "\n\r" and
"\r\n"
Original comment by nico.kru...@googlemail.com
on 26 Oct 2012 at 5:01
Committed r7651
Original comment by axelclk@gmail.com
on 26 Oct 2012 at 10:29
thanks, seems fixed now
Original comment by nico.kru...@googlemail.com
on 2 Nov 2012 at 10:59
Original issue reported on code.google.com by
nico.kru...@googlemail.com
on 26 Oct 2012 at 4:52Attachments: