If expr is missing in .(expr) or I(expr) in Pipe object in calling, it should be interpreted as doing nothing for conceptual consistent.
A useful case is that if one assign the closure to other symbols, directly calling the function without argument should show the current Pipe contents.
If
expr
is missing in.(expr)
orI(expr)
inPipe
object in calling, it should be interpreted as doing nothing for conceptual consistent.A useful case is that if one assign the closure to other symbols, directly calling the function without argument should show the current Pipe contents.