c++_1_3_5作業1

[roberthsu2003]

x = 1, y=1,2,3,4
x = 2, y=1,2,3,4
x = 3, y=1,2,3,4
x = 4, y=1,2,3,4
巢狀迴圈

int func2(int x, int y){
      xxxxxx;
     xxxxxxx;
    return xxxxx;
}

[ying0745]

#include <iostream>
#include <math.h>

using namespace std;

int fun1(int x, int y){
  double result = pow(x + y,3);
  return result;
}

int main() {
  for(int x = 1; x <= 4; x++){
    for(int y = 1; y <= 4; y++){
      int result = fun1(x,y);
      cout << result << endl;
    }
  }
}

[MoYingBaiMei]

#include <cmath>
#include <iostream>
using namespace std;

int f3(int x, int y);

int main() {
  int x, y;
  for (x = 1; x <= 4; x++) {
    for (y = 1; y <= 4; y++) {
      cout << f3(x, y) << endl;
    }
  }
}

int f3(int x, int y) {
  int ans = pow((x + y), 3);
  return ans;
}

[Lancehsu1030]

#include <iostream>
#include <math.h>
using namespace std;

int fun1(int x,int y) {
  double result = pow(x,3)+3*pow(x,2)*y +3*x*pow(y,2)+pow(y,3);
  return result;
}

int main() {
  for (int i = 1; i <= 4; i++) {
    for (int j = 1; j <= 4; j++) {
    int result =fun1(i,j);
    cout << result << endl;
    }
  }
}

[ChiuKuanHsun]

#include <iostream>
#include <math.h>

using namespace std;
int fun1(int x,int y)
{
  double result=pow(x, 3)+3*pow(x, 2)*y+3*x*pow(y, 2)+pow(y, 3);
  return result;
}

int main() {
  for (int i=1; i<=4; i++){
    for(int j=1; j<=4; j++){
      int result= fun1(i,j);
      cout<<result<<endl;
    }
  }
}

[Lancehsu1030]

？？？你的程式碼裡的方程式錯了應該是 double result=pow(x, 3)+3pow(x, 2)y+3xpow(y, 2)+pow(y, 3);缺了運算子 傳送自 Yahoo奇摩電子信箱 Android 版

在 2024 年 1月 月 4 日週四，時間：下午 9:18 ， Benjoe1017 @.***> 寫道：

`#include

include

using namespace std; int fun1(int x,int y) { double result=pow(x, 3)+3pow(x, 2)y+3xpow(y, 2)+pow(y, 3); return result; }

int main() { for (int i=1; i<=4; i++){ for(int j=1; j<=4; j++){ int result= fun1(i,j); cout<<result<<endl; } } } `

— Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you commented.Message ID: @.***>

[ChiuKuanHsun]

？？？你的程式碼裡的方程式錯了應該是 double result=pow(x, 3)+3pow(x, 2)y+3xpow(y, 2)+pow(y, 3);缺了運算子 傳送自 Yahoo奇摩電子信箱 Android 版 在 2024 年 1月 月 4 日週四，時間：下午 9:18 ， Benjoe1017 @.> 寫道： #include #include <math.h> using namespace std; int fun1(int x,int y) { double result=pow(x, 3)+3pow(x, 2)y+3xpow(y, 2)+pow(y, 3); return result; } int main() { for (int i=1; i<=4; i++){ for(int j=1; j<=4; j++){ int result= fun1(i,j); cout<<result<<endl; } } } — Reply to this email directly, view it on GitHub, or unsubscribe. You are receiving this because you commented.Message ID: @.> 應該是系統沒更新到，已改為正確的了

[a3137418]

#include <iostream>
#include <math.h>
using namespace std;
/*
x = 1, y=1,2,3,4
x = 2, y=1,2,3,4
x = 3, y=1,2,3,4
x = 4, y=1,2,3,4
巢狀迴圈*/

int func2(int x, int y){
  double result = pow((x+y) , 3);
  return result;
}

int main() {
  for (int i = 1; i <= 4; i++){
    for(int j = 1; j <= 4; j++){
      int result = func2(i,j);
      cout << result << endl;
    }  
  }
}

[FangYu0113]

#include <iostream>
#include <math.h>
using namespace std;

int fun(int x,int y)
{
    int answer = pow(x,3) + 3 * pow(x,2) * y + 3 * x * pow(y,2) + pow(y,3);
    return answer;
}

int main()
{
    for(int x=1;x<=4;x++)
    {
        for(int y=1;y<=4;y++)
        {
            int answer=fun(x,y);
            cout<<answer<<endl;
        }
    }
    return 0;
}