Closed robrix closed 8 years ago
I.e. x * 3 ++ y won’t compile because it’s parsed as x * (3 ++ y) instead of (x * 3) ++ y.
x * 3 ++ y
x * (3 ++ y)
(x * 3) ++ y
I.e.
x * 3 ++ ywon’t compile because it’s parsed asx * (3 ++ y)instead of(x * 3) ++ y.