Open KAEYL98 opened 3 years ago
Same issue here. Did you figure out a way to do this?
@KAEYL98
I'am using this module to download several images and need them stored with unique file names. file_name
is accessible by using .get
method of python dictionary.
results.metadata[0].get('_file')
You can try something like this:
results.metadata[0]['_file'] = 'file_name.jpg'
results.metadata
I slightly changed the api.py file, editing the results class as follows:
def __init__(
self,
params,
coordinates,
heading,
site_api='https://maps.googleapis.com/maps/api/streetview',
site_metadata='https://maps.googleapis.com/maps/api/streetview/metadata'):
...
self.params = params
self.coordinates = coordinates
self.heading = heading
...
for i, url in enumerate(self.links):
if metadata[i][metadata_status] == status_ok:
file_path = path.join(dir_path, coordinates + "_" + str(heading) + '.jpg')
metadata[i]['_file'] = path.basename(file_path) # add file reference
helpers.download(url, file_path)
in such a way, you can instantiate the results class passing as arguments the parameters, the lat,lon coordinates and the heading value. All become mandatory with such a solution:
results = google_streetview.api.results(params, "45.1234,15.759", "270")
the file name will be created accordingly by joining the lat-lon-heading values and no overwriting will occur.
Hi,
Is it possible to specify the filename of the downloaded images when using results.download_links()?
Thank you