rtoy
commented
1 week ago Imported from SourceForge on 2024-07-07 13:43:10 Created by dgildea on 2008-08-31 18:25:27 Original: https://sourceforge.net/p/maxima/bugs/1485/#f8b9
Logged In: YES user_id=1797506 Originator: NO
Fixed in limit.lisp rev 1.55.
(%i11) ex:(%pi*N^(2*N+1)*2^(2*N))/((2*N-1)^(2*N)*(2*%e*N+%e)); (%o11) %pi*N^(2*N+1)*2^(2*N)/((2*N-1)^(2*N)*(2*%e*N+%e)) (%i12) ex1:(%pi*N^(2*N+1)*4^N)/((2*N-1)^(2*N)*(2*%e*N+%e)); (%o12) %pi*N^(2*N+1)*4^N/((2*N-1)^(2*N)*(2*%e*N+%e)) (%i13) limit(ex, N, inf); (%o13) %pi/2 (%i14) limit(ex*%e, N, inf); (%o14) %e*%pi/2 (%i15) limit(ex1, N, inf); (%o15) %pi/2 (%i16) limit(ex1/%e, N, inf); (%o16) %e^-1*%pi/2 (%i17) limit(ex1*%e, N, inf); (%o17) %e*%pi/2
Imported from SourceForge on 2024-07-07 13:43:08 Created by andrejv on 2008-08-31 10:31:04 Original: https://sourceforge.net/p/maxima/bugs/1485
ex and ex1 are equivalent (replace 2^(2*N) with 4^N).
(%i1) ex:(%pi*N^(2*N+1)*2^(2*N))/((2*N-1)^(2*N)*(2*%e*N+%e)); (%o1) (%pi*N^(2*N+1)*2^(2*N))/((2*N-1)^(2*N)*(2*%e*N+%e)) (%i2) ex1:(%pi*N^(2*N+1)*4^N)/((2*N-1)^(2*N)*(2*%e*N+%e)); (%o2) (%pi*N^(2*N+1)*4^N)/((2*N-1)^(2*N)*(2*%e*N+%e)) (%i3) limit(ex, N, inf); (%o3) 0 (%i4) limit(ex*%e, N, inf); (%o4) inf (%i5) limit(ex1, N, inf); (%o5) %pi/2 (%i6) limit(ex1/%e, N, inf); (%o6) 0 (%i7) limit(ex1*%e, N, inf); (%o7) inf
The only correct answer is %o5. tlimit is correct for all examples.
Andrej