Open Matthias247 opened 5 years ago
Closing as a sub-issue of https://github.com/rust-lang/rust/issues/52924. (I've edited the top message in that thread to reference this one)
cc @tmandry @Zoxc
There definitely seems to be something causing locals to be unnecessarily put into the generator struct instead of staying as true-locals. Using a simplified function (with the same i_am_1kb
as above)
async fn composed() {
let inner = i_am_1kb();
{ let _foo = &inner; }
await!(inner);
}
and running cargo rustc -- -Z dump-mir=generator
to dump the mir, the liveness analysis shows that inner
is correctly considered dead after being moved to pinned
in the await!
macro (and so is not alive over a yield), but it is still being put in the generator.
@Nemo157 The generator transformation conservatively assumes that any borrow can be converted to a raw pointer and the locals can be accessed with that until their storage slot is dead. That's why inner
is considered live during the await!
here.
Yeah, @eddyb and I discussed this at the all-hands, and that making a type implement Copy
is actually a potential perf regression here, which is weird. For non-Copy
types, you can assume no accesses after moving out of them, but for Copy
types you can't necessarily do this.
Ok, so an optimisation to fix this example would be to add a less conservative check that can see when the borrow definitely wasn’t converted to a raw pointer. That seems relatively straightforward to check when the borrow never enters any unsafe code.
add a less conservative check that can see when the borrow definitely wasn’t converted to a raw pointer
Note that for this to be very useful at all it would have to be able to see through functions (via MIR inlining) and intrinsics (e.g. size_of_val
above).
Can it not trust the lifetimes on safe functions signatures? size_of_val
does not have a lifetime dependency so should be relied on to not stash a raw pointer to the reference away somewhere. (I guess this is an UCG question whether safe function boundaries are barriers that require safety to be upheld, and whether future unsafe code can allow prior safe code to violate lifetimes, i.e. is something like this sound or not).
No, lifetimes in function signatures cannot necessarily be used to determine the scope of accesses to the resulting pointer. Without a memory model it's completely unclear when accesses would or wouldn't be allowed to the underlying memory. @ralfjung's work on stacked borrows is the only thing I'm aware of that would allow proper analysis, and in general anywhere there's a ref-to-ptr conversion, all bets are sort of off.
I want to emphasize that this is still a problem even when the variable is not borrowed:
It doesn't matter whether the statement between the future generation and await! references the future or not. A simply println("") will have the same effect.
So there is likely progress to be made here without doing the analysis being discussed by @Nemo157 / @cramertj.
From skimming the MIR of
async fn composed() {
let inner = i_am_1kb();
{ foo(); fn foo() { } }
await!(inner);
}
it looks like that could be related to the unwind edge from the function call (and println!
expands to a few function calls). Another optimization related to the one mentioned in #52924 that could fix this would be to suppress moving values where their lifetimes only intersect during the move, essentially re-using the same stack slot for both inner
and pinned
(from inside await!
) and turning the move into a no-op.
(I tried a couple of other random snippets of code and couldn't see anything else done by println!()
that caused the doubled size).
EDIT: Actually, because of how drop chains work it looks like it's going to be more complex than that since inner
and pinned
have overlapping lifetimes, I have a simpler example for which I'll try and create a chart of the MIR and open a separate issue about this.
Opened https://github.com/rust-lang/rust/issues/59123 about the unwinding and drop interaction.
We discussed this issue and decided to label it as deferred for the purposes of stabilization -- it's a bit too broad. We might consider trying to fix specific instances of this problem. Certainly, to start, we would want to fix #52924 and revisit.
https://github.com/rust-lang/rust/issues/57478 contains a similar issue.
The size growth in this issue now goes away when the size_of_val
calls are replaced with an empty println!()
(this was #59123).
However, I think we should leave this issue open to track the general behavior that borrowing a future and then awaiting it causes us to double-allocate space for it, with #62321 tracking the specific case of size_of_val
.
Here's the solution I mentioned in https://github.com/rust-lang/rust/issues/62321#issuecomment-509351959:
foo(&x)
, we'll need to inline those functions in MIR so we can apply our analysis (1) to them.As noted by @cramertj and @withoutboats, there is an alternative that resolves most cases we care about: get rid of the move in await
. This requires
drop
with guaranteed move elision: either std::mem::drop
, or an internal one we can lower to (#62508)StorageDead
after it's dropped (#61015), so we don't break the existing optimization (PR #60187)I meant to say: Right now I prefer the approach of getting rid of the move in await
, unless we hit some unforeseen problem with it.
Resolving the general problem of borrow-then-move would be nice, but it doesn't seem like the most bang for our buck at this point.
It would be so much easier to do that drop in place and have borrowck understand the value is no longer accessible, if we were desugaring await
in MIR building.
We can probably use an intrinsic for this. I think move_init_val
has similar special handling?
Maybe a duplicate of #52924, but maybe also something else.
I observed that the sizes of
Future
s generated by async fns can grow exponentially. The following code shows an async fn, which produces a 1kB future. Each layering in another async fn doubles it's size:Output:
It doesn't matter whether the statement between the future generation and
await!
references the future or not. A simplyprintln("")
will have the same effect. Only if the future is directly awaited (as incomposed_1
) the size will stay constant.cc @cramertj , @nikomatsakis , @Nemo157