Closed GoogleCodeExporter closed 9 years ago
you can form the select in PHP but it doesn't have to use makeSelect(). You can
just create your would just switch to detect the col and the form an array like
so
remember the key of the array is the value attribute of the option and the
value of the array is the display of the option.
} else if(isset($_POST['select'])) {
switch($_POST['col']) {
case "whateverCol":
$array = array(
"0"=>"Dollar Off",
"1"=>"Percent Off"
);
echo json_encode($array);
break;
}
}
Original comment by Seancla...@gmail.com
on 11 Oct 2011 at 3:10
Original issue reported on code.google.com by
rodrigor...@gmail.com
on 24 Sep 2011 at 11:18