Open rzehumat opened 3 years ago
If E(a) == E(b) && Ig_b << Ig_a (i.e. order of 4), isotope b should be avoided.
E(a) == E(b) && Ig_b << Ig_a
b
That is a very serious issue, makes all results nonsense.
Roughly solved in #36
If
E(a) == E(b) && Ig_b << Ig_a
(i.e. order of 4), isotopeb
should be avoided.