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sail-sg / inceptionnext

InceptionNeXt: When Inception Meets ConvNeXt (CVPR 2024)
https://arxiv.org/abs/2303.16900
Apache License 2.0
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为什么7x7的深度卷积可以分解成3x3和1x11和11x1的深度卷积？ #3

Open EchoXu98 opened 1 year ago

EchoXu98 commented 1 year ago

您好！我想请问下，就是我标题中的问题“为什么7x7的深度卷积可以分解成3x3和1x11和11x1的深度卷积？” 这种分解是有严格数学推导吗？可以推导出分解前和分解后，二者的卷积核大小相同？还是因为效果好才这样分解？If you don't understand my question, I can ask it in English！

yuweihao commented 1 year ago

Hi @EchoXu98 ,

Thanks for your attention. "decompose" here is more like "replace" from the aspect of performance. Depthwise convolution and inception depthwise convolution are not mathematically equivalent.

sdu-huanhq commented 1 year ago

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

yuweihao commented 1 year ago

Hi @sdu-huanhq ,

Thanks for your attention. Yes, g is set as 1/8 by default in Table 1. Thanks for your reminder, I will add this information in the table caption in the next revision.

sdu-huanhq commented 1 year ago

Hi @sdu-huanhq ,

Thanks for your attention. Yes, g is set as 1/8 by default in Table 1. Thanks for your reminder, I will add this information in the table caption in the next revision.

Thanks for your answer and thumbs up for your work

yuweihao commented 1 year ago

Thanks for your answer and thumbs up for your work

Thank you so much!

116022017144 commented 1 year ago

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

I want to know where is the (2k+9) from?I know the C/8 is the parallel channel count

yuweihao commented 1 year ago

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

I want to know where is the (2k+9) from?I know the C/8 is the parallel channel count

2k from 1xk conv and kx1 conv and 9 from 3x3 conv.

116022017144 commented 1 year ago

oh，I know it.thank you

---原始邮件--- 发件人: "Weihao @.> 发送时间: 2023年5月8日(周一) 晚上9:32 收件人: @.>; 抄送: @.**@.>; 主题: Re: [sail-sg/inceptionnext] 为什么7x7的深度卷积可以分解成3x3和1x11和11x1的深度卷积？ (Issue #3)

您好，请问Inception dep. conv中的参数量(2k=9)C/8是怎么计算出来的？Inception dep conv的参数量应该和g的设置有关系吧。 Hello, may I ask how to calculate the parameter number (2k=9)C/8 in Inception dep. conv?

I want to know where is the (2k+9) from?I know the C/8 is the parallel channel count

2k from 1xk conv and kx1 conv and 9 from 3x3 conv.

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