Open Tristan-Liu-13 opened 10 months ago
I don't understand that you have Q(ci) = p(ci;xi, \theta), then why \sigma Q(ci) log Q(ci) is a constant? Looking forward to your reply.
I have the same question, i can not understand here.
I don't understand that you have Q(ci) = p(ci;xi, \theta), then why \sigma Q(ci) log Q(ci) is a constant? Looking forward to your reply.