Closed mochar closed 5 years ago
You can look at both residual types and evaluate their distributions. The vst
function accepts a residual_type
parameter which can be either pearson
or deviance
(pearson
by default)
For most genes the distribution of pearson residuals may show a long tail, but they have the nice property of mean 0 and variance 1 for non-differentially expressed genes. This is not true of the deviance residuals.
Thank you for the awesome response!
If not, are the deviance residuals any worse than the pearson residuals? I think they are normally distrubited right?