Closed Saatvik-droid closed 4 years ago
Suppose 'a' is a list. a.sort() will sort the list a within itself. So a1 = a.sort() is an issue as a is sorted as well as a1 and the algorithm is never tested.
I can do a pull request in a couple of days to fix that if that helps.
yup sure... submit a pr... i will review it👍🏻
Suppose 'a' is a list. a.sort() will sort the list a within itself. So a1 = a.sort() is an issue as a is sorted as well as a1 and the algorithm is never tested.
I can do a pull request in a couple of days to fix that if that helps.