Closed dani-vu closed 7 months ago
Hey @dani-vu,
That's something we have not yet implemented (see multi-output regression: #97). We only make for one time step ahead. Just to get more information about your issue, is this something that you would want to be implemented in MapieTimeSeriesRegressor
?
For the moment, the alternative would be to iteratively do one prediction at a time.
Thank you, Louis
Hey @LacombeLouis ,
thank you for the quick response. Yes, this is what I would want to be implemented in MapieTimeSeriesRegressor
.
All the best, Daniel
I want to use MAPIE to get prediction intervals. This works for a single step output approach. However, when I want to look e.g. 10 timestamps into the future, I get the "ValueError: y should be a 1d array, got an array of shape (8190, 10) instead."
I am using LSTM for this example. When having a single step output, my model looks like this:
model = Sequential([layers.Input(shape=(X_train.shape[1], X_train.shape[2])), layers.LSTM(64, return_sequences=True), layers.Flatten(), layers.Dense(32, activation='relu'), layers.Dense(32, activation='relu'), layers.Dense(1)])
For the multi step approach, I changed my last Dense layer parameter to the number of timestamps that I want to look into the future, in this case 10:
model = Sequential([layers.Input(shape=(X_train.shape[1], X_train.shape[2])), layers.LSTM(64, return_sequences=True), layers.Flatten(), layers.Dense(32, activation='relu'), layers.Dense(32, activation='relu'), layers.Dense(10)])
But as mentioned, the "ValueError: y should be a 1d array, got an array of shape (8190, 10) instead." occurs.
The shape of my X is (8190, 32, 23) and the shape of y is(8190, 10)).