How to pass a python dictionary as an argument into a function defined in LUA code?

[LeMoussel]

Hi,

I'm trying to pass a python dictionary as an argument into a function defined in LUA code but it crashes without exception. The Lua function returns the first non-empty parameter, or nil if they are all empty.

LUA code: lua/Article.lua

local Article = { }

function validTextArg( args, name, ... )
    local texte = args[name]
    if type( texte ) == 'string' and texte ~= '' then
        return texte
    elseif #{ ... } > 0 then
        return validTextArg( args, ... )
    end
end

function Article.article( args )
    -- validArg returns the first non-empty parameter, or nil if they are all empty.
    -- Only parameter names should be passed to the function.
    local validArg = function ( ... ) return validTextArg( args, ... ) or false end

    return validArg( 'périodique', 'revue', 'journal' )
end

return Article

Python code: main.py

    import lupa.lua54 as lupa

    lua = lupa.LuaRuntime(
        unpack_returned_tuples=True,
        register_eval=False,
    )
    print(
        f"Using {lupa.LuaRuntime().lua_implementation} (compiled with {lupa.LUA_VERSION})"
    )

    lua.execute("""
    local Article = require('lua/Article')
    function Tpl_Article(args)
        return Article.article(args)
    end
    """
    params = {
        'revue': 'Revue des langues romanes',
        'numéro': '105',
        'année': '2001',
        'pages': '503-517',
    }
    lua_result = lua.globals().Tpl_Article(params) # Crash

How do I invoke the LUA script and pass dictionary arguments ?

[pHiney]

Do you need to use something like : args["revue"] in your lua function ??? https://pypi.org/project/lupa/#python-objects-in-lua

I'm just looking at lupa now for my project.