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Spring时间参数自动转换 #34

Open seaswalker opened 3 years ago

seaswalker commented 3 years ago
  1. Get请求 这时应该使用Spring的注解: 
    @DateTimeFormat(pattern = DatePattern.NORM_DATE_PATTERN)
  2. POST json, Jackson 
    @JsonFormat(pattern = DatePattern.NORM_DATE_PATTERN)
  3. POST json, FastJson 
    @JSONField(format = DatePattern.NORM_DATE_PATTERN)