Closed sebastianwessel closed 5 months ago
Currently, if no object keys are explicit set, it will default to z.object({}), which isn't allowing any unknown entries.
z.object({})
This is correct, if the table is SCHEMAFULL, but not when set to SCHEMALESS.
Currently, if no object keys are explicit set, it will default to
z.object({})
, which isn't allowing any unknown entries.This is correct, if the table is SCHEMAFULL, but not when set to SCHEMALESS.