Closed zxy110 closed 6 years ago
It is the chanspec represented as a hexnumber, see https://github.com/seemoo-lab/nexmon/blob/master/patches/include/channels.h and keep the endianess in mind.
Jenny Doe notifications@github.com schrieb am Di., 17. Juli 2018, 08:11:
Hi, I'm confused the setting of argument, could you tell me why channel 100 with a bandwidth of 20 MHz is represented by 64d0? Thanks very much.
Jenny Doe
— You are receiving this because you are subscribed to this thread. Reply to this email directly, view it on GitHub https://github.com/seemoo-lab/mobisys2018_nexmon_channel_state_information_extractor/issues/10, or mute the thread https://github.com/notifications/unsubscribe-auth/ALP_7jYIp1X8dQbsmRTdzwVA82IbIT6Yks5uHYAngaJpZM4VSPR0 .
Thanks very much.
But I still confused about the setting of bandwidth . I don't know what's the connection of 20MHz with d0 . Do you know how it works ? Thanks a lot .
0xc0 = 5 GHz 0x10 = 20 MHz BW 0xc0 or 0x10 = 0xd0
Jenny Doe notifications@github.com schrieb am Fr., 27. Juli 2018, 10:35:
Thanks very much.
But I still confused about the setting of bandwidth . I don't know what's the connection of 20MHz with d0 . Do you know how it works ? Thanks a lot .
— You are receiving this because you commented. Reply to this email directly, view it on GitHub https://github.com/seemoo-lab/mobisys2018_nexmon_channel_state_information_extractor/issues/10#issuecomment-408351708, or mute the thread https://github.com/notifications/unsubscribe-auth/ALP_7gXMEo9dCGSec8r3v4ZnviufW0dGks5uKtDPgaJpZM4VSPR0 .
According to channels.c, 5GHz = 0xc000 20MHz = 0x1000 0xc000 or 0x1000 = 0xd000 Why is it 64d0 instead of d064?
Hi, I'm confused the setting of argument, could you tell me why
channel 100 with a bandwidth of 20 MHz
is represented by64d0
? Thanks very much.Jenny Doe