Closed sellout closed 14 years ago
(par a b c) is equivalent to (par a (par b c)) (or any permutation thereof), so the following code
(par a b c)
(par a (par b c))
(trigger {test (par {?name} ?remainder)} {test ?remainder}) {test (par {a} {b} {c})}
should result in {test (par {a} {b})} or {test (par {a} {c})} or {test (par {b} {c})}. But currently it doesn't react at all.
{test (par {a} {b})}
{test (par {a} {c})}
{test (par {b} {c})}
This depends on issue #8 being fixed.
As with #8, this is a problem for a new pattern language.
(par a b c)
is equivalent to(par a (par b c))
(or any permutation thereof), so the following codeshould result in
{test (par {a} {b})}
or{test (par {a} {c})}
or{test (par {b} {c})}
. But currently it doesn't react at all.