semanticarts / congr

Content Grapher
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Create a FileMetadata Class #26

Open stevenchalem opened 1 year ago

stevenchalem commented 1 year ago

ChatGPT wrote:

The code you shared is written in a procedural style and doesn't currently define any custom classes, so there are no methods or properties that could be moved to other classes in the current state of the code.

However, if you're interested in refactoring this into an object-oriented style, you could consider creating classes that encapsulate some of the functionality. Here's an example:

A FileMetadata class: This class could represent a single file or directory and its metadata. It could have properties like name, path, size, create_date, modify_date, etc. It could also have methods to calculate its own hash, to guess its MIME type, etc. This would encapsulate all the logic related to a single file or directory in a single class.

A MetadataGraph class: This class could represent the entire metadata graph. It would have a property for the RDFLib Graph, and it could have methods to add a FileMetadata object to the graph, to serialize the graph to a file, etc.

Here is a simple example of what the FileMetadata class could look like:

python Copy code class FileMetadata: def init(self, path): self.path = path self.name = os.path.basename(path) self.size = os.path.getsize(path) self.create_date = datetime.fromtimestamp(os.path.getctime(path)).isoformat() self.modify_date = datetime.fromtimestamp(os.path.getmtime(path)).isoformat() self.mime_type = mimetypes.guess_type(path)[0]

def get_hash(self):
    # implement the hashing function here
    pass

You would then use these classes in the main function like this:

python Copy code def generate_file_metadata(starting_dir_path, include_files, create_fingerprints, output_file='congr-output.ttl'): g = MetadataGraph()

for root, dirs, files in os.walk(starting_dir_path):
    dir_meta = FileMetadata(root)
    g.add_directory(dir_meta)

    for filename in files:
        file_meta = FileMetadata(os.path.join(root, filename))
        g.add_file(file_meta)

g.serialize(output_file)

Again, this is just an example and the details would depend on the exact requirements of your project. The current procedural style is perfectly fine for a script of this complexity, but an object-oriented style could be beneficial if the script grows larger or more complex.