Open lilsweetcaligula opened 3 years ago
It seems like Seneca.prototype.fail is ignoring log levels. In the code below, the call to #fail will produce the output despite the preceeding call to #quiet:
Seneca.prototype.fail
#fail
#quiet
const app = Seneca().quiet() app.fail('oops')
It seems like
Seneca.prototype.fail
is ignoring log levels. In the code below, the call to#fail
will produce the output despite the preceeding call to#quiet
: