sensenmercado / jpegcam

Automatically exported from code.google.com/p/jpegcam
GNU Lesser General Public License v3.0
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How to hide image? #32

Open GoogleCodeExporter opened 8 years ago

GoogleCodeExporter commented 8 years ago
When we are about take a picture the camera output is displayed on the screen. 
How do we take a snap without displaying the camera output on the webpage?

Original issue reported on code.google.com by khushish...@gmail.com on 2 Jun 2011 at 10:29

GoogleCodeExporter commented 8 years ago
In HTML File either remove hook for on Completion
I mean remove or comment this
webcam.set_hook( 'onComplete', 'my_completion_handler' );

or remove code from my_completion_handler() javascript function to not show 
image

Original comment by ashwin.r...@gmail.com on 2 Jun 2011 at 4:47

GoogleCodeExporter commented 8 years ago
The way this code works and starts the webcam and takes the picture and
allows for saving the image, do you by any chance hav a similar code for
fingerprint reader. I want a code that starts the fingerprint reader when a
page is loaded and allows for saving the fingerprint on the click event of a
button.

Original comment by khushish...@gmail.com on 7 Jun 2011 at 5:52

GoogleCodeExporter commented 8 years ago
This is my code for test.php
<?php

    $fname = $_POST['txtFname'];
    $lname = $_POST['txtLname'];
    $pno = $_POST['txtUname'];
    $pwd = $_POST['txtPwd'];
    $rpwd =$_POST['rtxtPwd'];

    $grade = $_POST['txtgrade'];

    $des=$_POST['desig'];
    $dep=$_POST['select'];
    $gender=$_POST['rad1'];

    $dateOB=isset($_REQUEST["date1"]) ? $_REQUEST["date1"] : "";
    $dateOJ=isset($_REQUEST["date2"]) ? $_REQUEST["date2"] : "";

$filename = 'Employee_pics/'.$_POST['txtUname'].date('YmdHis') . '.jpg';

if(!is_numeric($pno))
    {
        echo "Invalid Personal Number";
    }
    else if($pwd !== $rpwd)
    {
        echo "Password not Match";
    }
    else
    {
        // encrypting the password //
        //$pwd = md5($pwd);

        // connecting to database //
        $host="localhost"; // Host name
$user="root"; // Mysql username
$pass=""; // Mysql password
$db_name="hospital"; // Database name
$tbl_name="personal_table"; // Table name
// Connect to server and select databse.
$con = mysql_connect("localhost","root");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("$db_name")or die("cannot select DB");
        // checking username existance //

                        $result=mysql_query("select * from $tbl_name where pno=$pno");
         $count = mysql_num_rows($result) ;

        //$result = mysql_query($sql,$con);
        if($count==0)
        {

            // inserting user into tbl_user //
                    $sql1 = "insert into $tbl_name (pno, desig, grade, fname, lname, dob, dept, password, doj, gender, img ) values('$pno','$des','$grade','$fname','$lname','$dateOB','$dep','$pwd','$dateOJ','$gender','$filename')";

                        if (!mysql_query($sql1,$con))
                            {
                                        die('Error: ' . mysql_error());
                                    }

                        else
                                {

                                    $result = file_put_contents( $filename, file_get_contents('php://input') );
                                    $url = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['REQUEST_URI']) . '/' . $filename;
print "$url\n";
if (!$result) {
    print "ERROR: Failed to write data to $filename, check permissions\n";
    exit();
}
                                    }

        }       

        else
        {           

                    echo "Pno already exists.";

        }           

mysql_close($con);
}

?>
 but when the code is executed the image saved is an invalid image.
please help

Original comment by khushish...@gmail.com on 9 Jun 2011 at 6:01