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sercantutar / infint

Arbitrary-Precision Integer Arithmetic
http://sercantutar.github.io/infint/
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InfInt incorrectly represents INT_MIN when constructed directly #6

Closed maihde closed 7 years ago

maihde commented 9 years ago

INT_MIN will be incorrectly represented if you do InfInt(INT_MIN) because the constructor inverts the sign which causes an overflow. A patch has provided via a pull request.

sercantutar commented 7 years ago

solved this with latest commit