`pipe(gulp(dest))` actually works?

[stoplion]

Unless I'm misunderstanding, when running...

gulp.task('default', function() {
  return gulp.src('src/entry.js')
    .pipe(webpack())
    .pipe(gulp.dest('foobar/'));
});

a javascript file will never make to the dir foobar.

It just drops it in the dist, regardless of what gulp.dest you set.

Is this correct?

The destination is actually set in the webpack config and never the pipe(gulp(dest)) ?

[robchristian]

+1 on this. Not holding my breath about getting a response. Been almost 5 months and there's no reply to this issue.

[Backfighter]

Looking at the source code suggested that using dest() should actually work. Webpack-stream uses a virtual filesystem for webpack, so unless you pipe the output into dest it will not write any files to disk at all.

[navanshu]

Pass configs to your build maybe like this. The output directive is important.

.pipe(webpack({
        mode: "production",
        output: {
            filename: 'lazysizes.js',
          },
    }))