The change I requested in #63 that was implemented in #65 broke arguments with a default value of scalar types. The reason is that we were excluding null from the final type of the arg's value that's passed to the resolver, but since scalars can now be undefined, the type had to exclude that possibility too.
sikanhe
commented
2 years ago
The change I requested in #63 that was implemented in #65 broke arguments with a default value of scalar types. The reason is that we were excluding
nullfrom the final type of the arg's value that's passed to the resolver, but since scalars can now beundefined, the type had to exclude that possibility too.