Closed MBueschelberger closed 3 years ago
Thanks @MBueschelberger. I think this is almost ready except for one detail, that I noticed just after our conversation on Thursday. See the explanation below.
Imagine I execute the following code:
for citizen in result(age=int):
print(type(citizen['age']) is int)
break
Then the outcome is True
as we want.
But if afterwards I execute this other code
for citizen in result:
print(type(citizen['age']) is int)
break
As a user I would expect the outcome to be False
, but I get True
, because no dictionary update happened. Before merging we should solve this little problem.
If you have any idea just feel free to commit. I'll consider this to be my task too, so if I come up with something I may commit as well.
Thanks @MBueschelberger. I think this is almost ready except for one detail, that I noticed just after our conversation on Thursday. See the explanation below.
Imagine I execute the following code:
for citizen in result(age=int): print(type(citizen['age']) is int) break
Then the outcome is
True
as we want.But if afterwards I execute this other code
for citizen in result: print(type(citizen['age']) is int) break
As a user I would expect the outcome to be
False
, but I getTrue
, because no dictionary update happened. Before merging we should solve this little problem.If you have any idea just feel free to commit. I'll consider this to be my task too, so if I come up with something I may commit as well.
Yes, I can do so.
It passes the tests, so it works, but just to see how things would look in a real use case, I tried this with the UrWerk data.
[...]
for row in result(series='cuds', literal=float):
print(f"SPARQL result: {row['series'], row['literal']}.")
break
for row in result:
print(f"SPARQL result: {row['series'], row['literal']}.")
break
SPARQL result: (<mechanical.Series: 7f0b79aa-0bac-4aaf-b90d-f2945c7acfaf, AGraphSession: @0x7f9fdfad3940>, 161.011).
SPARQL result: (rdflib.term.URIRef('http://www.osp-core.com/cuds#4ae03ee7-b940-459e-9939-dd8db3c8e5c2'), rdflib.term.Literal('761.716', datatype=rdflib.term.URIRef('http://www.w3.org/2001/XMLSchema#double'))).
Looks nice. Thanks @MBueschelberger.
closes #655