SMPL model version

[Viki1314]

Hi @skhu101 ,Thanks a lot for sharing this very excellent work ! I have a problem about the smpl model during evaluation.I downloaded and used the SMPL_NEUTRAL of version 1.1.0 for Python2.7 from https://smpl.is.tue.mpg.de/download.php.But this smpl model has 300 shape PCs which means the shape of parameter'shapedirs' is (6890,3,300) instead of (6890,3,10). This would be incredibly helpful ! Thanks a lot !

[skhu101]

Hi, thanks for your interest in our work. The first 10 shape PCs should be used. If you have further questions, please let me know.

[Viki1314]

Thanks for your help!!! I have solved this problem.

[arnabdeypolimi]

How did you solve the problem?

[Viki1314]

How did you solve the problem?

import pickle
def smpl_pro():
model_paths = {
# 'neutral': os.path.join(model_dir, NEUTRAL_PATH)
# 'neutral': os.path.join(model_dir)
'neutral': os.path.join('assets/SMPL_NEUTRAL.pkl')
}
#import smpl        
with open(model_paths['neutral'], 'rb') as f:
smpl_model = pickle.load(f, encoding='latin1')
#reshape shapedirs
smpl_model['shapedirs'] = smpl_model["shapedirs"][:,:,:10]
#rewrite smpl
with open('smpl/assets/updated_data.pkl', 'wb') as f:
pickle.dump(smpl_model, f)

# with open(model_paths['neutral'], 'rb') as f:
#         smpl_model = pickle.load(f, encoding='latin1')
#check again
with open('smpl/assets/updated_data.pkl', 'rb') as f:
        smpl_model = pickle.load(f, encoding='latin1')
for key in smpl_model.keys():
    try:
        print(key,":",smpl_model[key].shape)
    except:
        print(key,":",smpl_model[key])