Closed 5j9 closed 9 years ago
Well, I did implement
In [2]: n = jdatetime.datetime(1395,1,1)
In [3]: n - jdatetime.timedelta(days=1)
Out[3]: jdatetime.datetime(1394, 12, 29, 0, 0)
But apparently forgot to implement what you need :(
it's fixed and pushed to pypi with version 1.7
Thanks!
When using the standard library:
but with jdatetime:
I'm using Python 3.5.0 (v3.5.0:374f501f4567, Sep 13 2015, 02:16:59) [MSC v.1900 32 bit (Intel)] on win32