Function template is removed while referenced as a function pointer

[mfornet]

If I pass as a default value to a function another function, the passed function is not kept (The minimal example I could reproduce was with functions using templates, which is my use case).

main.cpp

#include <iostream>
#include "lib.hpp"

int main()
{
    A a;

    std::cout << a.f() << std::endl;
}

lib.hpp

#include <functional>

using namespace std;

template <typename T>
T value()
{
    return 42;
}

class A
{
public:
    function<int()> f;

    A(function<int()> f = value<int>) : f(f)
    {
    }
};

result.cpp

#include <iostream>
#include <functional>

using namespace std;

class A
{
public:
    function<int()> f;

    A(function<int()> f = value<int>) : f(f)
    {
    }
};

int main()
{
    A a;

    std::cout << a.f() << std::endl;
}

Notice how declaration of function value was removed. If I use value without any templates it is not removed.

[slycelote]

Thanks for the bug report :) This has been fixed.