Closed vianneybacoup closed 6 months ago
When using the Increment.integer provider, with the start option, if the value given cannot be converted to i32 (so, higher than i64), the code will panic.
The Random.Number.i32 provider can be used as example as it has an extra check.
It's not happening actually
When using the Increment.integer provider, with the start option, if the value given cannot be converted to i32 (so, higher than i64), the code will panic.
The Random.Number.i32 provider can be used as example as it has an extra check.