Closed tautschnig closed 3 years ago
The two pointers that were being passed to free hold the same value on all execution paths, thus 1) resulting in a double-free and 2) making the fix as simple as removing the second call to free.
free
Fixes: #1257
The two pointers that were being passed to
free
hold the same value on all execution paths, thus 1) resulting in a double-free and 2) making the fix as simple as removing the second call tofree
.Fixes: #1257