Closed paulvha closed 3 years ago
Looking at the code for "write" the value of PDO2 voltage in NVRAM is done with:
// PDO2 sector[4][1] = voltage[1] / 0.2; //load Voltage (sector 4, byte 1, bits 0:7)
Looks to me this is not using the correct way to save it. why not apply the same approach for PDO3 (but then on a different place in the sectors)
// PDO2 // Load voltage (10-bit) // -bit 9:2 - sector 4, byte 1, bits 0:7 // -bit 1:0 - sector 4, byte 0, bits 7:6 digitalVoltage = voltage[1] / 0.05; //convert voltage to 10-bit value sector[4][0] &= 0x3C; //clear bits 7:6 sector[4][0] |= (digitalVoltage<<8); //load bits 1:0 sector[4][1] = 0xFF & (digitalVoltage >> 2); //load bits 9:2
regards, Paul
Thanks for pointing this out. This has been fixed with V1.1.5 release
Looking at the code for "write" the value of PDO2 voltage in NVRAM is done with:
Looks to me this is not using the correct way to save it. why not apply the same approach for PDO3 (but then on a different place in the sectors)
regards, Paul