If you compare the following Strings:
String* s = new String("foo");
String* t = new String("foobar");
then s equals t, according to String::compareTo(). Ofcourse, t should be > s.
Original issue reported on code.google.com by coenbijlsma on 11 Aug 2009 at 7:57
Original issue reported on code.google.com by
coenbijlsma
on 11 Aug 2009 at 7:57