Open arjunv27 opened 6 years ago
-- When we do: divide 5 2 -- This is evaluated as: ((divide 5) 2) -- First `divide 5` is evaluated. -- The argument `5` is applied to `divide`, resulting in an intermediate function.
Pretty sure the the function is applied to the argument. See this in the first paragraph.
I guess the correct word is a pedantic rather than pedagogic error
Pretty sure the the function is applied to the argument. See this in the first paragraph.