Open etanol85 opened 4 years ago
timkimber
commented
4 years ago Hi @etanol85
It's a benign error as that piece of code just checks whether the certificate needs renewing, when it fails the code just renews the certificate.
I've spent some time researching this and the date command on MAC OS 10.4.11 doesn't support what we need and without any way I can test I'm reluctant to try and use an alternative command.
rdebath
commented
4 years ago You may be interested in this ...
I use this awk program to mess with date ranges in my certificate script rather than trying to get date to work nicely everywhere. It works for Gregorian calendar dates from year one up on any awk derived from the '88 nawk version (basically all of them).
This gives "TODAY"
$ jdayjdat $(date '+%d %m %Y')
This gives "end date"
$ jdayjdat $(openssl x509 -noout -enddate -in cert.pem | sed 's/^[^=]*=//' | awk '{print $2,$1,$4;}')
#!/bin/sh -
jdayjdat() {
awk '#!/usr/bin/awk -f
BEGIN{
days[0] = "Sunday";
days[1] = "Monday";
days[2] = "Tuesday";
days[3] = "Wednesday";
days[4] = "Thursday";
days[5] = "Friday";
days[6] = "Saturday";
months["jan"] = 1;
months["feb"] = 2;
months["mar"] = 3;
months["apr"] = 4;
months["may"] = 5;
months["jun"] = 6;
months["jul"] = 7;
months["aug"] = 8;
months["sep"] = 9;
months["oct"] = 10;
months["nov"] = 11;
months["dec"] = 12;
if(ARGC == 2) {
j = ARGV[1]+0;
if (j>0 && j<65536) j += 2400000
split(jdate(j),A);
print A[1];
} else if(ARGC >= 4) {
d = ARGV[1]; m = ARGV[2]; y = ARGV[3];
if (d+0 > 999 && y < 100) { ms = d; d = y; y = ms; }
ms = tolower(substr(m, 1, 3));
if (ms in months) m = months[ms];
else {
ms = tolower(substr(d, 1, 3));
if (ms in months) {
d = m;
m = months[ms];
}
}
if( y>31 && y<70 ) y+=2000;
if( y>31 && y<100) y+=1900;
if( m<1) {m+=12; y--;}
if( m>12) {m-=12; y++;}
jd = jday(d,m,y);
if (ARGC > 4) {
printf("Input: %04d-%02d-%02d\n", y, m, d);
print jd
js = jdate(jd);
split(js,A,/[- ]/);
print js;
print A[1], A[2], A[3], days[A[4]];
} else
print jd
} else
print "Incorrect arguments"
}
function jdate(j, y,m,d,dow)
{
# Julian date converter. Takes a julian date (the number of days since
# some distant epoch or other) and returns the broken out date.
# d = day of month;
# m = month;
# y = year (actual year, like 1977, not 77 unless it was 77 a.d.);
# dow = day of week (0->Sunday to 6->Saturday)
# These are Gregorian.
# Copied from Algorithm 199 in Collected algorithms of the CACM
# Author: Robert G. Tantzen, Translators: Nat Howard, Robert de Bath
j = j + 1
dow = (j + 1)%7;
j -= 1721119;
# This should be a Euclidean division. But dates before 0001-01-01 dont
# make much sense anyway. Or even Friday, 15 October 1582 when the
# Gregorian calendar started.
y = int((4 * j - 1)/146097);
j = 4 * j - 1 - 146097 * y;
d = int(j/4);
j = int((4 * d + 3)/1461);
d = 4 * d + 3 - 1461 * j;
d = int((d + 4)/4);
m = int((5 * d - 3)/153);
d = 5 * d - 3 - 153 * m;
d = int((d + 5) / 5);
y = 100 * y + j;
if(m < 10) m += 3; else { m -= 9; ++y; }
return sprintf("%04d-%02d-%02d %d", y, m, d, dow);
}
function jday(d,m,y, c,ya,j)
{
# Takes a date, and returns a Julian day. A Julian day is the number of
# days since some base date (in the very distant past).
# Handy for getting date of x number of days after a given Julian date
# (use jdate to get that from the Gregorian date).
# Author: Robert G. Tantzen, translators: Nat Howard, Robert de Bath
# Translated from the algol original in Collected Algorithms of CACM
# (This and jdate are algorithm 199).
if(m>2) m -=3; else { m +=9; --y; }
c = int(y/100);
ya = y - (100*c);
j = int(146097*c/4) + int(1461*ya/4) + int((153*m+2)/5) + d + 1721119;
return j - 1;
}
' "$@"
}
jdayjdat "$@"
etanol85
commented
4 years ago Thank you timkimber and rdebath!
I just tried rdebath jdayjdat awk script, but it seems not to display the date correctly. When I ran jdayjdat $(date ’+%d %m %Y’) it prints 2459026 and today it is 26-06-2020, date gives: Fri Jun 26 09:02:29 CEST 2020
Am I missing something?
timkimber
commented
4 years ago Hi @etanol85
I found out recently that github actions support MacOS so I'll write a test for this scenario and post an update.
When running getssl mydomain.com under MAC OS 10.4.11
I see the folowing error: usage: date [-nu] [-r seconds] [+format] date [[[[[cc]yy]mm]dd]hh]mm[.ss]
The script seems to continue despite this error but I don’t know if it works correctly.
man date gives: DATE(1) BSD General Commands Manual DATE(1)
NAME date -- display or set date and time
SYNOPSIS date [-nu] [-r seconds] [+format] date [-u] mmddhhmm[[cc]yy]
DESCRIPTION date displays the current date and time when invoked without arguments. Providing arguments will format the date and time in a user-defined way or set the date. Only the superuser may set the date.
ENVIRONMENT VARIABLES The following environment variables affect the execution of date :
FILES /var/log/wtmp A record of date resets and time changes. /var/log/messages A record of the user setting the time.
EXAMPLES The command:
DIAGNOSTICS The following exit values are returned: 0 The date was written successfully (either locally or globally) DIAGNOSTICS The following exit values are returned: 0 The date was written successfully (either locally or globally)
LEGACY SYNOPSIS date [-nu] [-r seconds] [+format]
LEGACY DIAGNOSTICS When invoked in legacy mode the following exit values are returned: 0 The date was written successfully 1 Unable to set the date 2 Able to set the local date, but unable to set it globally
SEE ALSO gettimeofday(2), strftime(3), compat(5), utmp(5), timed(8)
STANDARDS The date utility supports the Version 3 of the Single UNIX Specification (
SUSv3''). It is also expected to be compatible with IEEE Std 1003.2 (POSIX.2'').BSD September 22, 2004 BSD (END)