pb中uint64过长, 在decode时会被科学计数法

运行代码

local pb = require "pb"
local protoc = require "protoc"

-- 直接载入schema (这么写只是方便, 生产环境推荐使用 protoc.new() 接口)
assert(protoc:load [[
   message Phone {
      optional string name        = 1;
      optional sfixed64  phonenumber = 2;
   }
   message Person {
      optional string name     = 1;
      optional int32  age      = 2;
      optional string address  = 3;
      repeated Phone  contacts = 4;
   } ]])

-- lua 表数据
local data = {
    name = "ilse",
    age  = 18,
    contacts = {
        { name = "alice", phonenumber = 12312341234 },
        { name = "bob",   phonenumber = 7822518873084182062 }
    }
}

-- 将Lua表编码为二进制数据
local bytes = assert(pb.encode("Person", data))
print(pb.tohex(bytes))
-- 再解码回Lua表
local data2 = assert(pb.decode("Person", bytes))
print(require "serpent".block(data2))

输出结果:

10 12 22 10 11 F2 6A DF DD 02 00 00 00 0A 05 61 6C 69 63 65 22 0E 11 2E BE F8 36 78 2B 8F 6C 0A 03 62 6F 62 0A 04 69 6C 73 65
{
  age = 18,
  contacts = {
    {
      name = "alice",
      phonenumber = 12312341234
    } --[[table: 0x7f99f310bee0]],
    {
      name = "bob",
      phonenumber = 7.8225188730841825e+18
    } --[[table: 0x7f99f310bf50]]
  } --[[table: 0x7f99f310bea0]],
  name = "ilse"
} --[[table: 0x7f99f310bd10]]

我的lua版本是5.4.6 正常的number输出是没有问题的

有好心人能帮忙看下嘛

starwing / lua-protobuf

pb中uint64过长, 在decode时会被科学计数法 #252