Closed zxdawn closed 2 years ago
Ha, I see. The second method has been added:
harp.concatenate([product_1, product_2])
As long as cond1
and cond2 & cond3
are fully distinct sets, you can indeed ingest them individually and concatenate the results.
cond2 & cond3
is also already possible by using cond2;cond3
.
Having a more elaborate combination of filters would actually require the solution that is mentioned in #249. So I am closing this issue in favor of that one.
Let's say I have three conditions: cond1, cond2, and cond3. I wanna create an operation which is
cond1 | (cond2 & cond3)
. This is equal to merging two products:I read through the Doc and both of them aren't supported yet.